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Oduvanchick [21]
3 years ago
15

Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even

ts or going to the movies.
Among tenth graders, what is the relative frequency of preferring sporting events? Express your answer as a decimal, and round to the nearest hundredth if necessary

Mathematics
1 answer:
Elis [28]3 years ago
4 0
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

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yulyashka [42]

Answer:

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3 years ago
Urgent!!!!?
ExtremeBDS [4]

Answer:

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The diagram is shown in the attachment.

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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
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Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

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Triangle DEF is 20% smaller than the original, which means its side is:

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<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

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3 years ago
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