Answer:
The <em>p</em>-value of the test is 0.0512.
Step-by-step explanation:
The <em>p</em>-value of a test is well-defined as per the probability, [under the null hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.
In this case the output of the t-test_ind method from scipy module is provided as follows:
Output = (-1.99, 0.0512)
The first value within the parentheses is the test statistic value.
So the test statistic value is, -1.99.
And the second value within the parentheses is the <em>p</em>-value of the test.
So the <em>p</em>-value of the test is 0.0512.
The answer is 21 because if you subtract 17 from 17 and 38 you get 21. Z=21.
You would make all the fractions have the same common denominator of 12. First you would keep the fraction 7/12 because the denominator is already 12. Next you would take the fraction 1/3 and multiply it by 4/4 and the new fraction for 1/3 becomes 4/12. Lastly you would take 2/3 and multiply that by 4/4 and the fraction becomes 8/12. Now you can compare the fractions with the same denominator. Therefore 7/12 is greater than 1/3 but less than 2/3
First you grapgh 0,-3 then you follow the slope of going 4 up 5 to the right and contine up also on e-where it is 0,-3 you go down 4 and 5 to the left and contine that to make a straught line.
18. equivalent
16x5 does equal 10x8
19. equivalent
13-0 does equal 0
20. Not equivalent
12-2 doesn’t not equal 7-3
For all three of these equations you have to use PEMDAS (systems of equations) so first you solve everything that’s in parentheses, then any exponents, followed by multiplication,division,addition, and lastly subtraction. You MUST follow that order to get the correct answer.
