Answer:
0.9177
Step-by-step explanation:
let us first represent the two failure modes with respect to time as follows
R₁(t) for external conditions
R₂(t) for wear out condition ( Wiebull )
Now,
where t = time in years = 1,
n = failure rate constant = 0.07
Also,
where t = time in years = 1
where Q = characteristic life in years = 10
and B = the shape parameter = 1.8
Substituting values into equation 1
Substituting values into equation 2
let the <em>system reliability </em>for a design life of one year be Rs(t)
hence,
Rs(t) = R1(t) * R2(t)
t = 1
![Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713](https://tex.z-dn.net/?f=Rs%281%29%20%3D%20%5Be%5E%7B-0.07%7D%20%5D%20%2A%20%5Be%5E%7B-0.0158%7D%20%5D%20%3D%200.917713)
Rs(1) = 0.9177 (approx to four decimal places)
Answer:
i say yes
Step-by-step explanation:
this is because it will give you the point to start with and the slope so you will already have all the information to graph
5x - 2y + 1z = 8 ⇒ 5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9x - 2y - 5z = 4 -4x + 3z = 13
5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9z - 2y - 5z = 4 ⇒ -9x - 2y - 5z = 4
-18x - 3z = 9
-4x + 3z = 13
-18x - 3z = 9
-22x = 22
-22 -22
x = -1
-18x - 3z = 9
-18(-1) - 3z = 9
18 - 3z = 9
- 18 - 18
-3z = -9
-3 -3
z = 3
5x - 2y + z = 8
5(-1) - 2y + 3 = 8
-5 - 2y + 3 = 8
-2y - 5 + 3 = 8
-2y - 2 = 8
+ 2 + 2
-2y = 10
-2 -2
y = -5
(x, y, z) = (-1, -5, 3)
Answer:
1) No
2) No
3)Yes
4)No
Step-by-step explanation:
Distributive property: a(b + c) =a*b + a*c
1) 4(5c + 3) = (4*5c) + 4*3
= 20c + 12
NO
2) 2(8f - 5) = (2*8f) - (2*5)
= 16f - 10
NO
3) 3(4g + 7) = (3*4g) + (3*7)
= 12g + 21
YES
4) 6(4j - 6) =(6 * 4j) - (6*6)
= 24j - 36
NO
1/2=4/8. 3 and 4/8+ 3 and 3/8 is 6 and 7/8.
