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Alexeev081 [22]
3 years ago
5

kayla is standing in the gym watching the PE teacher toss volleyballs into the ball bin. She estimates that the PE teacher's han

d is 4 feet above the gym floor, the ball bin is 4 feet high and she is standing 10 feet from the ball bin while the maximum height of the ball is 8 feet. quadratic equation.
Mathematics
1 answer:
miss Akunina [59]3 years ago
3 0

Answer:

pp

Step-by-step explanation:

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G(x) = -3x2 - 4x + 12, find g(-4).
Hoochie [10]

Answer:

Your answer is -20

Hope that this is helpful. Vote and like it

8 0
3 years ago
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The perimeter of a rectangle is 70 cm. The ratio of length to width is 2:5. Find the length and width of the rectangle.
olya-2409 [2.1K]

Answer:

length = 10 cm; width = 25 cm

Step-by-step explanation:

Let's call the length 2x and the width 5x. Since perimeter can be calculated by multiplying the sum of the length and width by 2 we can write:

2 * (2x + 5x) = 70

2 * (7x) = 70

7x = 35

x = 5 which means the length is 2 * 5 = 10 and the width is 5 * 5 = 25.

5 0
3 years ago
2^n=8^20. Solve for n
damaskus [11]

Hi the answer is 60 but the picture will show you the work!!

3 0
3 years ago
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A statue in the park is 24 feet tall and has a width of 36 inches. Chase was in
NeTakaya

Answer:

<u>22.33 feet tall / 267.96 inches tall</u>

Step-by-step explanation:

The statue is 36 inches wide. If Chase made his model of the statue 16 inches wide, he decreased it by 20 inches. Now change the inches into feet. 36 inches would be 3 feet, 16 inches would be 1.33 feet and 20 inches would be 1.67 feet. <u>24ft - 1.67 = 22.33ft.</u> Now change the answers to inches.  22.33ft will be 267.96 inches tall.

3 0
3 years ago
Can you help me with my work
andrezito [222]

Answer:

1. x = ±9

2. x=\pm \sqrt{13}

3. 12 and -12.

4. Antoine is incorrect. There exists two solutions x=5 and x= -5.

Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.

Thus, the options are 12 and -12.

Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.

8 0
3 years ago
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