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Fynjy0 [20]
2 years ago
14

1. What volume is shown in the graduated cylinder below?

Chemistry
1 answer:
hram777 [196]2 years ago
4 0

The volume shown in the graduated cylinder according to the image would 28 mL. Thus, the correct option would be C.

In the cylinder, the top of the liquid formed a concave meniscus with the walls of the cylinder. Thus, the bottom of the meniscus would be read as this is the normal rule.

The rule is such that for liquids that form concave meniscus with the walls of cylinders, the bottom of the meniscus is read while it is the top of the meniscus for liquids that form convex meniscus with the walls of cylinders.

Hence, looking at the image, the bottom of the concave is on the 28 mL mark on the cylinder.

More on concave and convex meniscus can be found here: brainly.com/question/17022999

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Which phase change is exothermic?
DerKrebs [107]
Freezing, condensation, Deposition.
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3 years ago
Which of the following would release the most heat? Assume the same mass of in each case. Specific heats of ice, liquid water, a
lesya692 [45]

Answer:

The process which releases most heat is E)

Explanation:

As we know that water freezes at 0ºC and vaporizes at 100ºC, we calculate the heat as follows:

  • Processes with temperatures < 0ºC : by using specific heat of ice (Sh ice) multiplied by the change in temperature (ΔT= Final Temperature - Initial Temperature)⇒ Sh ice x ΔT
  • Processes of ice melting (at 0ºC): by using heat of fusion of ice (ΔH fus) multiplied by a conversor factor (1 mol H20= 18 g)⇒ ΔHfus x 1mol/18g
  • Processes between 0ºC and 100ºC: by using specific heat of liquid water (Sh liq) multiplied by change in temperature ⇒ Sh liq x ΔT
  • Processes of water evaporation (at 100ºC): by using heat of vaporization (ΔH vap) multiplied by the conversor factor ⇒ ΔH vap x 1mol/18 g
  • Processes at a temperature >100ºC: by using specific heat of water vapor (Sh vap) multiplied by the change in temperature ⇒ Sh vap x ΔT

A) Water at -25ºC is ice. Ice is heated from -25ºC to 0ºC, then it melts at 0ºC (ice became liquid water) and then liquid water is heated from 0ºC to 70ºC. T

This is the only process in with the heat is absorbed (not releases), so it cannot be the right answer, but we calculate the heat involved to practice:

Heat= (Sh ice x ΔT) + (ΔH fus x 1/18 g) + Sh liq x ΔT

Heat= (2.05 J/g ºC x (0ºC -(-25ºC) ) + (6.01 x 10³ J/mol x 1 mol/18 g) + (4.18 J/g ºC x (70ºC-0ºC)

Heat= 51.25 J + 333,8 J +292.6 J

Heat= 677.65 J (heat is absorbed)

B) Water is cooled from 13ºC to 0ºC, then it is freezed at 0ºC and then the ice is cooled from 0ºC to -2.6 ºC

Heat= (Sh liq x ΔT) + (-ΔH melt x 1/18 g) + (Sh ice x ΔT)

Heat= 4.18 J/ºC x (0ºC- 13ºC) + (-6.01 x 10³ J/mol x 1mol/18 g) + (2.05 J/ºC x (-2.5ºc - 0ºC)

Heat= -54.34 J - 333.8 J + 5.33 J

Heat= -393.47 J (heat is released)

C) Liquid water is cooled from 74ºC to 95ºC

Heat= Sh liq x ΔT

Heat= 4.18 J/ºC x (74ºC - 95ºC)

Heat = -87.78 J (heat is released)

D) Water at 140ºC is in vapor state. Vapor at 140ºC is cooled to 110ºC (still vapor).

Heat = Sh vap x ΔT

Heat= 2.01 J/ºC x (110ºC - 140ºC)

Heat= -60.3 J (heat is released)

E) Vapor at 106ºC is cooled to 100ºC, then it condenses at 100ºC (convertion from gas to liquid), and liquid water is cooled from 100ºC to 88ºC.

Heat= (Sh vap x ΔT) + (-ΔHvap x 1mol/18g) + (Sh liq x ΔT)

Heat= (2.01 J/ºC x (100ºC-106ºC)) - (40.7 x 10³ J/mol x 1mol/18 g) + (4.18 J/ºC x (88ºC -100ºC)

Heat= -2323.32 J (heat is released) <u>THIS IS THE RIGHT ANSWER</u> (the more negative= the more released)

7 0
3 years ago
An atom has 6 electrons in its outer orbit. It will most likely form an ion with a charge of:
GenaCL600 [577]

Answer:

c

Explanation:

4 0
3 years ago
Oxygen gas is collected over water. The total pressure (the O2 pressure the water vapor pressure) is 736 torr. The temperature o
tigry1 [53]

Answer:

The value of the partial pressure of the oxygen  P_{O_{2} } =  690 torr

Explanation:

Total pressure of the mixture of gases = 736 torr

The partial pressure of water vapor = 46 torr

From the law of pressure we know that

Total pressure = The partial pressure of water vapor + The partial pressure of oxygen O_{2}

Put the values of pressures in above equation we get,

⇒ 736 = 46 + P_{O_{2} }

⇒ P_{O_{2} } = 736 - 46

⇒ P_{O_{2} } =  690 torr

This is the value of the partial pressure of the oxygen.

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Reactions rates for reactions occurring in solution can be increased by increasing the concentration of the solution. With gases
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"Increase Pressure " is the right answer. if you need help , let me know
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3 years ago
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