A piece of an unknown substance weighing 124.0 grams is heated in boiling water to 100.0oc. when the substance is placed in a ca
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Answer:
Density of the liquid = 1470.43 kg/m³
Explanation:
Given:
Mass of solid sphere(m) = 6.1 kg
Density of the metal = 2600 kg/m³
Thus volume of the liquid :
Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³
The volume of water displaced is equal to the volume of sphere (Archimedes' principle)
Volume displaced = 0.002346 m³
Buoyant force =
Where
is the density of the fluid
g is the acceleration due to gravity
V is the volume displaced
The free body diagram of the sphere is shown in image.
According to image:
Acceleration due to gravity = 9.81 ms⁻²
Tension force = 26 N
Applying in the equation to find the density of the liquid as:
<u>Thus, the density of the liquid = 1470.43 kg/m³</u>
Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is .
Explanation:
The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.
Now, in terms of chemical formulae this reaction equation will be as follows.
Here, number of atoms on reactant side are as follows.
- Mn = 1
- O = 2
- H = 1
- Cl = 1
Number of atoms on product side are as follows.
- Mn = 1
- O = 1
- H = 2
- Cl = 4
To balance this equation, multiply HCl by 4 on reactant side and multiply by 2 on product side. Therefore, the equation can be rewritten as follows.
Hence, number of atoms on reactant side are as follows.
- Mn = 1
- O = 2
- H = 4
- Cl = 4
Number of atoms on product side are as follows.
- Mn = 1
- O = 2
- H = 4
- Cl = 4
Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.
Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is .