Answer:
1.553 M^2s^-1
Explanation:
Now let us consider experiments 1,2,3.
In experiment 1 and 2, the concentration of NO is doubled and the initial rate of reaction is quadrupled.
0.575/0.144 = 4
So;
2^2 =4
In experiment 2 and 3
The concentration of reaction of H2 is doubled and the rate of reaction is doubled.
0.575/0.287 = 2
2^1 =2
So we can now write;
Rate =k[NO]^2 [H2]^1
Taking up the first reaction;
0.144 =k [0.475]^2 [0.411]
k = 0.144/ [0.475]^2 [0.411]
k = 1.553 M^2s^-1
It’s Neon (Ne). You know because there are 10 protons and the number of protons is equal to the atomic number of an element. (Neon is #10 on the periodic table)
Answer: Benzene is less reactive than methylbenzoate and more reactive than Nitrobenzene
Explanation:
This is because the methyl group on the benzene ring is an electron donating group leading to the activation of the ring and subsequently leading to more canonical resonance structure at the intermediate stage of the reaction enhancing the faster reactivity
However for the Nitrobenzene the nitro group is an electron withdrawing group leading to a slower activation and less resonance canonical structure at the reaction intermediate leading to a slower reaction than the reaction of benzene without the nitro group
The answer is d it released c02
112 L/ 16 L = 7 mol O2
7 mol O2 x 2 mol Fe2O3/ 3 mol O2 = 4.67 mol Fe2O3
lmk if its right