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3 years ago

Which half-reaction correctly shows the oxidation of iron

Chemistry

1 answer:

VLD [36.1K]3 years ago

6 0

Answer: The half-reaction correctly shows the oxidation of iron $Fe\rightarrow Fe^{2+}+2e^-$

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

The oxidation of iron is represented as:

$Fe\rightarrow Fe^{2+}+2e^-$

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

The reduction of iron is represented as:

$Fe^{2+}+2e^-\rightarrow Fe$

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3 years ago

Express the following numbers as decimals: (a) 1.52 x 10^-2, (b) 7.78 x 10^-8, (c) 1 x 10^-6, (d) 1.6001 x 10^3.

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Answer :

(a) 0.0152

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(c) 0.000001

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Explanation :

Scientific notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example :

5000 is written as $5.0\times 10^3$

889.9 is written as $8.899\times 10^{-2}$

In this examples, 5000 and 889.9 are written in the standard notation and $5.0\times 10^3$ and $8.899\times 10^{-2}$ are written in the scientific notation.

(a) $1.52\times 10^{-2}$

The standard notation is, 0.0152

(b) $7.78\times 10^{-8}$

The standard notation is, 0.0000000778

(c) $1\times 10^{-6}$

The standard notation is, 0.000001

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3 years ago

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3 years ago

If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater density? ball A,

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Density (D) is defined as the amount or mass (m) of a substance present in a unit volume(V). It can be expressed mathematically as:

Density = Mass/Volume

i.e. D = m/V -------(1)

Units: g/cm3

If m1, V1 and D1 = mass, volume and density respectively of ball A

m2, V2 and D2 = mass, volume and density respectively of ball B

It is given that: V1 = V2; but m1 = 2m2

Based on equation (1) we have:

D1/D2 = (m1/V1)* (V2/m2) = (2m2/V2)*(V2/m2) = 2

Thus, density of ball A is twice that of B.

Ans: Ball A will have a greater density than B

If m1, V1 and D1 = mass, volume and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

It is given that:

V1 = 3V2 and m2 = 1/3(m1) i.e m1 = 3m2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (3m2/3V2)*(V2/m2) = 1

Thus, D1 = D2

Ans: Their densities are equal

If m1, V1 and D1 = mass, volume and density respectively of ball P

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It is given that:

m1 = m2 but V1 = 2V2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (m2/2V2)*(V2/m2) = 1/2

Thus, D1 = 1/2(D2)

Ans: Ball Q will have a greater density.

If m1, V1 and D1 = mass, volume and density respectively of ball X

m2, V2 and D2 = mass, volume and density respectively of ball Y

It is given that:

V1 = 2V2 and m1 = 1/2(m2)

Therefore,

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Thus, D1 = 1/4(D2)

Ans: Ball Y will have a greater density.

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