Answer:
1. C. helium
2. D. oxygen and acetylene
3. B. deliquescence
4. C. cutting very hard surfaces
5. B. 3.5%
Explanation:
I think it would be better control of fusion reactions.
Answer:
1.4×10-37
Explanation:
The equation for the dissolution of the copper II phosphate is first written as shown and the ICE table is set up as also shown. S is obtained as shown and this is now used to obtain 2s and subsequently the solubility product of the calcium phosphate as shown in detail in the image attached to this solution. The step-by-step solution shows how to obtain Ksp when concentration at equilibrium is given.
The equation is as follow,
<span> HBr </span>₍aq₎ + H₂O ₍l₎ →
Solution:
HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,
HBr ₍aq₎ + H₂O ₍l₎ → H₃O⁺ ₍aq₎ + Br⁻ ₍aq₎
Answer: 1.875 moles
Explanation:
2 NaN3(s) → 2 Na(s) + 3 N2(g)
From the equation above, Sodium azide has a chemical formula of NaN3 while nitrogen gas has a chemical formula of N2.
Therefore, If on decomposition
2 moles of NaN3 produce 3 moles of N2
1.25 mol of NaN3 produce Z moles of N2
To get the value of Z, cross multiply
Z x 2 moles = 3 moles x 1.25 moles
2 moles•Z = 3.75 moles²
Divide both sides by 2 moles
2 moles•Z/2 moles = 3.75 moles²/2 moles
Z = 1.875 moles
Thus, 1.875 moles of N2 are produced by the decomposition of 1.25 mol of sodium azide
