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Damm [24]
3 years ago
14

Three balanced coins are tossed independently. One of the variables of interest is Y1, the number of heads. Let Y2 denote the am

ount of money won on a side bet in the following manner.
If the first head occurs on the first toss, you win $1. If the first head occurs on toss 2 or on toss 3 you win $2 or $3, respectively. If no heads appear, you lose $1 (that is, win −$1)
a. Find the joint probability function for Y1 and Y2.

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Find the below attachments for detailed answer.

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Write each mixed number as a decimal.<br> 1.) 4 1/5 <br> 2.) 12 14/15<br> 3.) 5 5/32
bezimeni [28]
I showed you how to do it in the picture.

<span>Answers:
1.) 4 1/5 = 4.22.) 12 14/15 = 12.93 (3 is repeating so draw a line on top of just the 3)<span>3.) 5 5/32 = 5.156 (the 56 is repeating so draw a line on top of just the 56)

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6 0
3 years ago
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motikmotik

Answer:

1A, 2C, 3X, 4A, 5B, 6W, 7X

Step-by-step explanation:

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5 0
4 years ago
Answer ASAP!
valentinak56 [21]

Answer:

A and D

Step-by-step explanation:

Since tangent is opposite/adjacent,

Tan 40 in this case would be x/3.8 (i used x because we don't know what the value is)

So, you set it up as an algebra problem

Tan40 = x/3.8

Multiply both sides by 3.8

3.8tan40 = x, Option A

And then, angle E is 50 degrees

So tan 50 = 3.8/x

Multiply both sides by x

tan50x = 3.8

Divide both sides by tan50

x= 3.8/tan50

So, A and D are both correct

3 0
2 years ago
4 7/12 + 2 1/12 what is the estimate answer
Pani-rosa [81]
4 \frac{7}{12} =  \frac{12*4+7}{12} =  \frac{55}{12}  \\  \\ 2 \frac{1}{12} =  \frac{2*12+1}{12} =  \frac{25}{12}  \\  \\  \frac{55}{12} +  \frac{25}{12} =  \frac{80}{12}  \\  \\  \frac{80 :4}{4:4}  =  \frac{20}{3}
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saul85 [17]

34 x 57 = 1,938 petals is the correct answer :)

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3 years ago
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