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Natali5045456 [20]
3 years ago
9

On Saturday, many tickets for a hockey game were sold. Children and adult tickets were sold in the ratio of 4:7. There are 88 ti

ckets in total.
How many adult tickets were sold?
Mathematics
1 answer:
Illusion [34]3 years ago
6 0

Answer:

49 tickets

Step-by-step explanation:

THis is pretty straight forward

So we have the ratio 4:7

We know there were 88 tickets in total but we don’t know the exact amount of adult and kids

So we can Add up the ratio

4+7=11

Now we can divide 88 by 11

you’ll get 7

So by doing this we know there are 7 groups of the ratio for child to adults 4:7

So we just multiply the 7 to each

4*7

7*7

you’ll get 28:49

Now we know there are 28 kid tickets and 49 adult tickets

We know this is correct becuase if you add up the ratio, it’ll be 88

Which is the same as the amount fo people at the hockey game

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I need help ASAP. Thank you :)
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m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

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If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

m∠CBF + m∠BFD = 180°

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<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

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m∠DFE = m∠DEF

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