Question

What is the area of triangle ABC?

Answer 1

Answer:

$\circ\ \ 36\sqrt{3}$

Step-by-step explanation:

$CD=12\times \sin(60) =12\times \frac{\sqrt{3} }{2}$

Important Note:………………………………………………………………………………………

ABC is an equilateral triangle because it has 2 angles of measure 60

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According to the note AB = 12

Final answer :

$\text{Area of triangle ABC} =\frac{AB\times CD}{2}$

                                  $=\frac{12\times 6\sqrt{3} }{2}$

                                  $=\frac{72\sqrt{3} }{2}$

                                  $=36\sqrt{3}$