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marusya05 [52]
3 years ago
12

Estimate the total number of books at Woodside

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0

Answer:

whats the question add the rest

Step-by-step explanation:



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The sum of a four angles of quality is 180 true or false​
ehidna [41]

Answer:

the sum of a four angles of quadrilateral is 180.<u>False</u>

<u>Note</u><u>:</u><u> </u><u>its</u><u> </u><u>3</u><u>6</u><u>0</u><u>°</u>

8 0
3 years ago
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What is the area of the square adjacent to the third side of the triangle?
lana66690 [7]

Answer:

The area of the square adjacent to the third side of the triangle is 11 units²

Step-by-step explanation:

We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,

x² = 33,

x = \sqrt{33} .... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.

x² = 44,

x = \sqrt{44} .... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.

Let x = the length of the side of the unknown square's area -

\sqrt{(44)}^2 = x^2 + \sqrt{33}^2,

x = \sqrt{11} ... And \sqrt{11} squared is 11, making the area of this square 11 units².

3 0
4 years ago
Read 2 more answers
Solve for -5/6*n=40<br><br> 56<br><br> 48<br><br> -48<br><br> -56
oee [108]

Solve for -5/6*n=40

n = 40/(-5/6)

n = 40 * -6/5

n = -48

answer n= -48

5 0
3 years ago
Solve 5x+4y=-30<br> 3x-9y=-18<br> Solve using the elimination method
jenyasd209 [6]

Answer:

  (x, y) = (-6, 0)

Step-by-step explanation:

The y-coefficients have opposite signs, so we can eliminate y-terms by multiplying both equations by a positive number and adding the results.

9 times the first equation plus 4 times the second gives ...

  9(5x +4y) +4(3x -9y) = 9(-30) +4(-18)

  45x +36y +12x -36y = -270 -72 . . . . eliminate parentheses

  57x = -342 . . . . . collect terms

  x = -6 . . . . . . . divide by the coefficient of x

__

Substituting into the first equation gives ...

  5(-6) +4y = -30

  4y = 0 . . . . . . . . . add 30

  y = 0

The solution is (x, y) = (-6, 0).

4 0
2 years ago
The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?
Alexxx [7]

Answer:

Perimeter = 22.809836694575                              

Step-by-step explanation:

A(-2, 2)  ;  B(6,2)  ;  C(0, 8)

AB=\sqrt{\left( 6--2\right)^{2}  +\left(2-2 \right)^{2}  } =\sqrt{64} =8

AC=\sqrt{\left( 0--2\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{40} =2\sqrt{10}

BC=\sqrt{\left( 0-6\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{72} =6\sqrt{2}

Then

The perimeter of ΔABC = AB + BC + AC

                                       =8+6\sqrt{2} +2\sqrt{10}

                                       = 22.809836694575

3 0
3 years ago
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