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3 years ago

1/3x+y=10/8;1/6x+1/5y=13/6. what is the solution set?

1 answer:

7 0

1/3x+y=10/8
Times 1/2 for both side
1/6x+1/2y=5/8
-
1/6x+1/5y=13/6
=
3/10y=-1/2
Divided 3/10 for both side
y=-5/3

1/3x+y=10/8
1/3x-5/3=10/8
1/3x=70/24
1/3x=35/12
x=35/4
x=8 3/4. As a result, the solution set is (8 3/4,-5/3). Hope it help!

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Answer:

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2 years ago

Erica had 6 coins in her coin collection. she goes to a coin show and buys some coins. how many dose she have now?

Anuta_ua [19.1K]

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3 years ago

Please help, no fake answers and please...

alex41 [277]

Answer:

a = 5120

b = 1.25

Step-by-step explanation:

Let the exponential function representing the given table is,

f(x) = $a(b)^x$

Here, f(x) = Number of views

x = Number of weeks

We choose two points from the given table and satisfy the equation of the function.

Let the points are (0, 5120) and (1, 6400)

For a point (0, 5120),

f(0) = a(b)⁰ = 5120

a = 5120

Now for the second point (1, 6400),

6400 = 5120(b)¹

b = $\frac{6400}{5120}$

b = 1.25

Therefore, a = 5120 and b = 1.25 are the values.

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2 years ago

Read 2 more answers

How is the quotient 80,000÷2000 different from the quotient 80,000÷200 or 80,000÷20

Olegator [25]

2,000, 200 and 20 are similar except for the number of zeros.
You can remove a zero from each to equal the number of zeros in the divisor. So 80,000 ÷ 2,000 is equivalent to 80 ÷ 2 = 40 you just remove the 3 zeros
80,000 ÷ 200 is equivalent to 800 ÷ 2 = 400 you just keep removing 0s like for instance this time it was 2 lastly 80,000 ÷ 20 only allows us to remove 1 zero 8,000 ÷ 2 = 4,000. The smaller the divisor the greater the quotient when dividing the same number like for instance in this example 80,000

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3 years ago

The price of a computer component is decreasing at a rate of 15% per year. State whether this decrease is linear or exponential

Margaret [11]

Answer:

Since the price is given by an exponential function, the decline in price is exponential.

The component will cost $36.8475 in three years.

Step-by-step explanation:

The equation for the price of a component has the following format:

$P(t) = P(0)(1-r)^{t}$