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Assoli18 [71]
3 years ago
11

A group of eight friends (five girls and three boys) plans to watch a movie but they have only five tickets how many different c

ombinations of five friends could possibly receive the tickets
Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

1- all five girls

2- four girls and one boy

3. three girls and two boys

4. two girls and three boys.

4 combinations

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What are all real square roots of .027​
mario62 [17]

Answer:

Step-by-step explanation:

The principal, real, root of:

^{2} \sqrt{0.027}

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All roots:

0.164316767

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Drag each tile to the table to multiply each row heading by each column heading
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Answer:

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lutik1710 [3]
<h3>Answer:</h3>

4.42×10^34 molecules/min

<h3>Step-by-step explanation:</h3>

Multiply the various factors, along with the unit conversion (60 s/min).

... (3.35×10^25 molecules/L) × (2.2×10^7 L/s) × (60 s/min)

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7 0
3 years ago
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AlladinOne [14]

Answer:

32

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7 0
3 years ago
2.1x10^6<br> ______<br> 7x10^3<br><br> answer in standard form<br> ...................10^......
VMariaS [17]

Given:

The expression is:

\dfrac{2.1\times 10^6}{7\times 10^3}

To find:

The simplified form of the given expression in standard form.

Solution:

We have,

\dfrac{2.1\times 10^6}{7\times 10^3}

It can be written as:

\dfrac{2.1\times 10^6}{7\times 10^3}=\dfrac{21\times 10^5}{7\times 10^3}

\dfrac{2.1\times 10^6}{7\times 10^3}=\dfrac{21}{7}\times \dfrac{10^5}{10^3}

\dfrac{2.1\times 10^6}{7\times 10^3}=3\times 10^{5-3}        [\because \dfrac{a^m}{a^n}=a^{m-n}]

\dfrac{2.1\times 10^6}{7\times 10^3}=3\times 10^2

Therefore, the required value is 3\times 10^2.

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3 years ago
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