Assuming linear.
if k is at (3,4) and j is at (-8,7)
set. (y1,x1) and(y2,x2)
[(y2-y1),(x2-x1)]
[(-8-3),(7-4)]
distance from k to j is (-11,3)
now take coordinates of j and distance from. k->j and add them to get coordinate for L
[(-11+(-8)),(7+3)]= (-19,10)=L
Answer:
b = -³¹⁄₃
Step-by-step explanation:
We can solve this Algebra equation by separating the variable and constants.
3b + 15 = -26 - 20
3b + 15 = -46
3b = -31
b = -³¹⁄₃
Answer:
Canadian railcars show weight figures in both imperial and metric. Canadian railways also maintain exclusive use of imperial measurements to describe train length and height in feet and train masses in short tons. Canadians typically use a mix of metric and imperial measurements in their daily lives.
Answer:
About 38.48ft
Step-by-step explanation:
A=
A=
A≈38.48
First term is -7, so a_1 = -7
To get the next term, we add on 4. We can see this if we subtract like so
d = (2nd term) - (1st term) = (-3) - (-7) = -3+7 = 4
So d = 4 is the common difference.
Apply a_1 = -7 and d = 4 to get...
a_n = a_1 + d*(n-1)
a_n = -7 + 4*(n-1)
a_n = -7 + (n-1)*4
Answer: Choice A
