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2 years ago

Steve was training for a race, he ran 3/4 of a

Mathematics

2 answers:

mestny [16]2 years ago

4 0

Answer:

29/28 miles or 1 1/28 miles

Step-by-step explanation:

So Steve ran 3/4 mile on Monday and 2/7 more miles of Tuesday.

So on Tuesday Steve ran 3/4 + 2/7 miles

We find a common denominator, 28

3/4 = 21/28 2/7 = 8/28

21/28 + 8/28 = 29/28 or 1 1/28 miles on Tuesday

wariber [46]2 years ago

3 0

Answer:

0.28571 miles (keystrokes)

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Tim must read 2 books from a list of 7 recommended books for his summer reading program. In how many different ways can Tim choo

Marianna [84]

There are 21 ways Tim choose 2 books from the 7 recommended book

Solution:

Given that Tim must read 2 books from a list of 7 recommended books for his summer reading program

To find: different ways can Tim choose 2 books from the 7 recommended books

This is a combination problem

A combination is a selection of all or part of a set of objects, without regard to the order in which objects are selected

The formula for combinations is:

$n C_{r}=\frac{n !}{r !(n-r) !}$

where n represents the number of items, and r represents the number of items being chosen at a time

Here we have to choose 2 books from 7 books

Therefore, n = 7 and r = 2

Substituting values in above formula, we get

$\begin{aligned}&7 C_{2}=\frac{7 !}{2 !(7-2) !}\\\\&7 C_{2}=\frac{7 !}{2 ! \times 5 !}\end{aligned}$

For a number n, the factorial of n can be written as,

$n !=n \times(n-1) \times(n-2) \dots \dots \times 2 \times 1$

Therefore, we get

$7 C_{2}=\frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1 \times 5 \times 4 \times 3 \times 2 \times 1}\\\\7C_2 = 7 \times 3 = 21$

Thus there are 21 ways Tim choose 2 books from the 7 recommended book

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3 years ago

2 _ x -7=11 5 whats the answer

ZanzabumX [31]

Answer:

x=45

Step-by-step explanation:

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2 years ago

11y^2-19y-10=-4y^2 all real solutions

tangare [24]

Answer:

y=5/3 is the only real solution

Step-by-step explanation:

Solve for y over the real numbers:

11 y^2 - 19 y - 10 = -4 y^2

Add 4 y^2 to both sides:

15 y^2 - 19 y - 10 = 0

The left hand side factors into a product with two terms:

(3 y - 5) (5 y + 2) = 0

Split into two equations:

3 y - 5 = 0 or 5 y + 2 = 0

Add 5 to both sides:

3 y = 5 or 5 y + 2 = 0

Divide both sides by 3:

y = 5/3 or 5 y + 2 = 0

Subtract 2 from both sides:

y = 5/3 or 5 y = -2

Divide both sides by 5:

Answer: |

| y = 5/3 or y = -2/5

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3 years ago

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Kisachek [45]

Answer:

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Step-by-step explanation:

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3 years ago

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