B because pie radius square = area of a circle
Answer would be D You can have a rational discriminant for an irrational root, but you can also have rational discriminant for a rational root. So C is partially correct.
<span>All prime discriminants will result in an irrational root, but not all irrational roots have prime discriminants </span>
Answer
4
Step-by-step explanation:
Answer:
1c 2b
Step-by-step explanation:
Answer:
7 adults, 12 students
Step-by-step explanation:
10 20 30 40 50
60 70
74 78 82 86 90
94 98 102 106 110 114 118
