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meriva
2 years ago
8

In addition, what is the inverse

Mathematics
1 answer:
insens350 [35]2 years ago
5 0

Answer:

it is

-3/7=3/7

brainliest s

if u want

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Marking people as BRAINLIST
Gnesinka [82]

Answer:

66

Step-by-step explanation:

57 x 2= 114

180-114= 66

5 0
2 years ago
Ashley ate Mexican food 4 out of 7 days on her vacation. If her vacation was 35 days, how many days did she eat Mexican food?
lina2011 [118]

The number of days Ashley ate Mexican food while on vacation is 20 days.

<h3>How many days did Ashley eat mexican food?</h3>

The first step is to determine the fraction of the number of days Ashley atae Mexican food. In order to do this, divide 4 by 7

4/7.

The second step is to multiply 4/7 by 35

4/7 x 35= 20 days

To learn more about multiplication, please check: brainly.com/question/3385014

8 0
2 years ago
Please could someone help me?
Sonja [21]

Answer:

∠ XZY ≈ 23.6°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin Z = \frac{opposite}{hypotenuse} = \frac{XY}{YZ} = \frac{6}{15}, thus

Z = sin^{-1}(\frac{6}{15}) ≈ 23.6° ( to 1 dec. place )

3 0
3 years ago
Read 2 more answers
Find the area of a circle with a diameter of 5 cm.
slavikrds [6]

Answer:

5 squares the times it by pi (pi equals 3.14 btw)

Step-by-step explanation:

5 squared is 25

6 0
3 years ago
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
3 years ago
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