What is the maximum number of real distinct roots that a cubic equation can have?

Mathematics

2 answers:

Hoochie [10]3 years ago

5 0

3 but in most cases it is 2 real roots and one root has a multiplicity of 2

gogolik [260]3 years ago

4 0

an degree polynomial can have as many as n real roots.

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jamie wants to run a total of 9 miles thid week. so far, she has run 4 5/8 miles. use the equation 4 5/8 + r = 9. please help m

____ [38]

Answer:

$r=4\frac{3}{8}$

Step-by-step explanation:

Given the following question:

$4\frac{5}{8} +r=9$

Rewrite the expression to find the value of r:

$9-4\frac{5}{8}$

Subtract by finding the common denominator:
$9-4\frac{5}{8}$
$9=\frac{9}{1}$
$4\frac{5}{8} =8\times4=32+5=37=\frac{37}{8}$
$\frac{9}{1} -\frac{37}{8}$
$\frac{9}{1} \times8=\frac{72}{8}$
$\frac{37}{8} \times1=\frac{37}{8}$
$\frac{72}{8} -\frac{37}{8}$
$72-37=35$
$=\frac{35}{8}$
$\frac{35}{8} =35\div8=4\frac{3}{8}$
$r=4\frac{3}{8}$
$4\frac{5}{8} +4\frac{3}{8} =9$

Hope this helps.