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Readme [11.4K]
3 years ago
13

A balloon drifts 50 m toward the east in 6 s; then the wind suddenly changes and the balloon flies 30 m toward the west in the n

ext 5 s. What was the balloon's total displacement?
Physics
1 answer:
dybincka [34]3 years ago
5 0
Displacement of an object is equal to distance from starting point to end point.

Let's use positive numbers for movement towards east and negative numbers fro movements towards west. First movement is +50m, second movement is -30m. We add these numbers to find displacement.
d=+50m-30m \\ d=20m

Total displacement is 20m towards east.
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Magnitude of desired magnetic field, E=0\ N.C^{-1}

Let q be the positive charge magnitude placed at origin.

<u>We know the distance between the two Cartesian points is given as:</u>

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

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\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }

\therefore (1-0)^2+(8-0)^2=r^2

r^2=65\ nm

r=\sqrt{65}

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the  given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

x=2\times 1=2\ nm

and

y=2\times 8=16\ nm

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