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777dan777 [17]
3 years ago
14

Anyone help me !!!!!!!!!!!

Mathematics
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

idk the first 2 but the 3rd one is QR and QT

Step-by-step explanation:

those are the lines on either side of 1.

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Laptop computers are measured according to the diagonals of their screens. A 16-inch laptop has a screen that is 7 inches tall.
disa [49]
Approximately 14.4 inches I think is the correct answer!
6 0
3 years ago
Please help marking people as BRAINLIST
romanna [79]
I believe the answer is 8
3 0
2 years ago
Richie spent $120 on 12 rose bushes and 2 gardenias, while Jim spent it $150 on 10 rose bushes and 10 gardenias. What is the cos
Basile [38]
With the given information, we can create several equations:

120 = 12x + 2y
150 = 10x + 10y

With x being the number of rose bushes, and y being the number of gardenias.

To find the values of the variables, we can use two methods: Substitution or Elimination

For this case, let us use elimination. To begin, let's be clear that we are going to be adding these equations together. Therefore, in order to get the value of one variable, we must cancel one of them out - it could be x or y, it doesn't matter which one you decide to cancel out. Let's cancel the x out:

We first need to multiply the equations by numbers that would cause the x's to cancel out - and this can be done as follows:

-10(120 = 12x + 2y)
 12(150 = 10x + 10y) => Notice how one of these is negative

Multiply out:

    -1200 = -120x - 20y
 +  1800 =  120x + 120y          => Add these two equations together
---------------------------------
600 = 100y

Now we can solve for y:

y = 6

With this value of y known, we can then pick an equation from the beginning of the question, and plug y in to solve for x:

120 = 12x + 2y    =>    120 = 12x + 2(6)

Now we can solve for x:

120 = 12x + 12    =>     108 = 12x

x = 9

So now we know that x = 9, and y = 6.

With rose bushes being x, we now know that the cost of 1 rose bush is $9.
With gardenias being y, we now know that the cost of 1 gardenia is $6.  
4 0
3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

5 0
3 years ago
OMG PLEASE HELP IF I DONT PASS THIS I FAIL MY CLASS! HELP! 30 POINTS SHOW WORK IF U NEED TO PLEASE! thank you too anyone(PRETTY
Molodets [167]

Answer:

C seems right to me

Step-by-step explanation:

8 0
3 years ago
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