PLEASE HELP URGENT

Mathematics

1 answer:

Blababa [14]2 years ago

5 0

Answer:

see attached

Step-by-step explanation:

The two different triangles can be formed by placing the 90° angle adjacent to, or opposite the given side.

In the attached diagram, the two triangles are ABC and ABD. The right angles are at vertex C and vertex B, respectively.

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Which of the following is a false statement? Solid substances need different temperature of heat to melt them. All solid substan

maria [59]

Answer:

All solid substances require the same temperature and heat to melt them.

Step-by-step explanation:

Depending on the substance, the required heat to melt it changes, and is not the same for every solid.

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3 years ago

On Naomi's cell phone plan, the amount she pays each month for international text messages is proportional to the number of inte

egoroff_w [7]

A. Constant of proportionality in this proportional relationship is; k=5

B. Equation to represent this proportional relationship is : c=t/k

Step-by-step explanation:

A.Given that : the amount she pays each month for international text messages is proportional to the number of international texts she sends, then

$3.20 k = 16 ---------where k is the constant of proportionality

k= 16/3.20 =5

k=5

B. Let c be the cost of sending the texts per month and t be the number of texts sent per month , so

c=t/k

c=t/5 ---------- is the proportionality relationship.

For t=16 , c= 16/5 =$3.20

Learn More

Proportionality :brainly.com/question/11490054

Keywords: cell phone plan, month, international texts, proportional,paid

#LearnwithBrainly

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3 years ago

Solve for y 16y^2-25=0

Pepsi [2]

Answer:

$\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

Step-by-step explanation:

$16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}$

$METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$