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Marizza181 [45]
1 year ago
13

A carpenter cuts the corners of a rectangle to make the trapezoid shown.

Mathematics
1 answer:
lozanna [386]1 year ago
4 0

The value of x in the trapezoid is 11.

<h3>Properties of an isosceles trapezoid</h3>
  • The base angles are the same
  • The sum of opposite angles is 180° or supplementary.
  • The diagonals are the same in length.

Therefore, the angle 9x and 7x + 4 are supplementary.

Hence,

9x + 7x + 4 = 180

16x + 4 = 180

16x  = 180  - 4

16x = 176

x = 176 / 16

x = 11

learn more on trapezoid here: brainly.com/question/18651035

#SPJ1

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She will have 1$ left

Step-by-step explanation:

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Which of the following numbers is divisible by 6?
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Andrea made a replica of the Empire State Building. The surface area of the model is 45 ft2. What is the surface area of the act
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Answer:

<u>87,120 ft²</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Surface area of the Empire State building replica = 45 square feet

Scale factor = 44

2. What is the surface area of the actual Empire State Building in square feet?

For answering the question, we will make the following calculations:

45 square feet = 9 feet * 5 feet or,

45 square feet = 10 feet * 4.5 feet, or,

45 square feet = 20 feet * 2.25 feet.

Now, let's apply the scale factor to all of these probable lengths of the sides of the surface area of the replica, as follows:

(9 *44) * (5 * 44) = 396 * 220 = 87,120 ft²

(10 * 44) * (4.5 * 44) = 440 * 198 = 87,120 ft²

(20 * 44) * (2.25 * 44) =  880 * 99 = 87,120 ft²

<u>As we proved, no matter what are the lengths of the sides of the surface area of the replica. after applying the scale factor, the result is the same: 87,120 ft²</u>

6 0
3 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
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Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
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There are 12 pens at first and 20 pencils.
After 1 pen is taken, 11 pens are left.
After 5 pencils are taken, 20-5=15 pencils are left.
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