Answer:
6 $50 bills and 9 $5 bills
Step-by-step explanation:
Let's let x = the number of $5 bills, and y = the number of $50 bills. With this, we can set up two equations:
5x + 50y = 345
x + y = 15
Because there is $345 total in the register, that means that 5 times the number of $5 bills plus 50 times the number of $50 bills would equal 345. And there are 15 bills total, so the numbers added is 15. Now, we can solve these equations through substitution:
x + y = 15
x = 15 - y
Now, plug in (15 - y) for x into the other equation, and solve for y:
5(15 - y) + 50y = 345
75 - 5 y + 50y = 345
75 + 45y = 345
45y = 270
y = 6
Since y is 6, that means we have 6 $50 bills. And there are 15 bills total, so there are 9 $5 bills. (15 - 6 = 9)
