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vesna_86 [32]
2 years ago
11

A sample of a gas has volume 78.5ml at 318.15 K.. What Volume at will the sample occupy at

Chemistry
2 answers:
expeople1 [14]2 years ago
5 0

Charles'law:

V₁/T₁=V₂/T₂

78.5/318.15 = V₂/273.15

V₂=67.4 ml

Natali [406]2 years ago
5 0

<u>Required</u><u> </u><u>answer</u><u> </u><u>:</u>

We know that,

Charle's Law :

  • \red{\boxed{ \sf \frac{V_{1}}{T_{1}} \:  =  \: \frac{V_{2}}{T_{2}} }} \:  \pink \bigstar

We have :

  • V_1 = 78.5 ml
  • T_1 = 318.15 K
  • T_2 = 273.15 K
  • V_2 = ?

(V is volume and T is temperature)

Substituting the values :

\implies \: \sf \dfrac{78.5}{318.15} \:  =  \: \dfrac{ V_2}{273.15} \\  \\ \implies \: \sf 78.5 \times273.15  \: =  \:  V_2 \times 318.15 \\  \\ \implies \: \sf { 21442.275 \:  =  \:  V_2 \times 318.15} \\  \\\implies \: \sf {V_2  =   \dfrac{ 21442.275 }{318.15}}  \\  \\  \implies \: \bf {V_2  =  67.3 \: (approx) }

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