Question

A sample of a gas has volume 78.5ml at 318.15 K.. What Volume at will the sample occupy at

Answer 1

Charles'law:

V₁/T₁=V₂/T₂

78.5/318.15 = V₂/273.15

V₂=67.4 ml

Answer 2

Required answer :

We know that,

Charle's Law :

• $\red{\boxed{ \sf \frac{V_{1}}{T_{1}} \: = \: \frac{V_{2}}{T_{2}} }} \: \pink \bigstar$

We have :

• V_1 = 78.5 ml
• T_1 = 318.15 K
• T_2 = 273.15 K
• V_2 = ?

(V is volume and T is temperature)

Substituting the values :

$\implies \: \sf \dfrac{78.5}{318.15} \: = \: \dfrac{ V_2}{273.15} \\ \\ \implies \: \sf 78.5 \times273.15 \: = \: V_2 \times 318.15 \\ \\ \implies \: \sf { 21442.275 \: = \: V_2 \times 318.15} \\ \\\implies \: \sf {V_2 = \dfrac{ 21442.275 }{318.15}} \\ \\ \implies \: \bf {V_2 = 67.3 \: (approx) }$