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3 years ago

Please hurry!!! This is a test! I'll mark brainliest! +50

Chemistry

2 answers:

OLga [1]3 years ago

6 0

Answer:

1. D

2. B

3. A

4. A

5. C

6. B

7. D

8. A

9. B

10. A

11. B

12. B

13. C

14. B

15. D

Explanation:

Nikitich [7]3 years ago

3 0

Answer:

1. D.

Explanation:

It is the only one possible

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why is it essential to know the water temperature in this experiment- to find the vapor pressure of the water

Oksi-84 [34.3K]

Answer:

Vapour pressure of a liquid varies with temperature

Explanation:

The vapour pressure of any liquid is directly proportional to the temperature of the liquid. This implies that, as the temperature of the liquid increases, the vapour pressure increases likewise and vice versa.

Since the vapour pressure of liquid varies with the temperature of the liquid, it is essential to know the water temperature in the experiment to determine the vapour pressure of water.

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3 years ago

What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?

mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

$C=\frac{n}{V}$ .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is $K_{2}SO_{4}$ thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

Putting the values,

$n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol$

Thus, number of moles of $K_{2}SO_{4}$ will be $0.1061\times 0.5=0.053 mol$ .

The volume of solution is 225 mL, converting this into L,

$1 mL=10^{-3}L$

Thus,

$225 mL=0.225 L$

Putting the values in equation (1),

$C=\frac{(0.053 mol}{0.225 L}=0.236 M$

Therefore, concentration of potassium sulfate solution is 0.236 M.

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3 years ago

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sertanlavr [38]

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3 years ago

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mafiozo [28]

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3 years ago

What is the pressure of 1.50 moles of a gas in a 30.0L tank at a temperature of 285K?

julia-pushkina [17]

The pressure of the gas : 1.1685 atm

<h3>Further explanation</h3>

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

n=moles=1.5

V=volumes = 30 L

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The pressure :

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7 0

3 years ago