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Lesechka [4]
3 years ago
15

Which terms represent two types of organic reaction

Chemistry
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

Saponification and fermentation .

Explanation:

Hello,

In this case, we define:

- Sublimation as such physical change (the substance does not change its composition) from solid to gases by adding heat.

- Deposition as such physical change (the substance does not change its composition) from gas to solid by heat withdrawal.

- Saponification as such chemical change (the substance does changes its composition) which consists on the conversion of a fat, oil or lipid  by adding  heat in the presence of aqueous strong base such as NaOH or KOH into soap and alcohol.

- Fermentation as a biochemical change that produces chemical changes in organic substrates by the action of biocatalysts called enzymes. It typically turn glucose into piruvate, ethanol or short organic acids.

For that reason, both fermentation and saponification are chemical reactions, more specifically organic reactions since the reactants are mainly carbon-based.

Best regards.

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Pastoral farming is best described as _______. A. A method of raising livestock and moving herds b. An African method of agricul
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Pastoral farming is best described as a method of raising livestock and moving herds.

<h3>What is pastoral farming</h3>

Pastoral farming is a system of farming that aims at producing animals rather than crops.

In pastoral farming, the herd of animals are moved from one place to another in search of food and water.

Therefore, pastoral farming is best described as a method of raising livestock and moving herds.

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5 0
3 years ago
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I need help with number two
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The temperature is held constant at (b) and (d). At these points, the substance is changing states. B is changing from solid to liquid and D is changing from liquid to gas
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Why do farmers spray water over their crops before a frost?
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When water freezes and turns into ice, it releases latent heat. Then, the ice that builds up on the plant will insulate it from the colder surrounding air temperatures. Because of this, some growers choose to spray their crop with water before the freeze occurs.

Explanation:

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3 years ago
You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add
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your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

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3 years ago
A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of he antacid was added to 200 m
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Answer:

a) 8.33 ml of the original stomach acid is neutralized

b) 191.67 ml of the stomach acid was neutralized

c)  249.68 ml acid would be neutralized by the original tablet

Explanation:

a) how much of the stomach acid had been neutralized in the 25 mL sample wich was titrated?

25.5 ml of a NaOH solution is equivalent to 25.00 ml of the original stomach acid

8.5 ml NaOH * (25.00 ml original stomach acid / 25.5 ml NaOH) = 8.33 ml original stomach acid

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It takes 8.5 ml NaOH to neutralize 8.33 ml original acid (this is the answer for question 1)

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c) how much stomach acid would have been neutralized by the original 5.6832 g tablet

4.3628 g antacid is equivalent to 191.67 ml acid  ( this is the answer for question 2)

5.6832g antacid * (191.67 ml acid / 4.3628 g antacid) = 249.68 ml acid

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3 years ago
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