First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively.
6.) (9y-3)/(y^2-5)
8.) 3/xy^3
Two find a common denominator, find the smallest value that has BOTH denominators as factors.
10.) 8x^3*y^3 is the common denominator
Answer: 2/(8*x^3*y^3)
12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)
Therefore, x+2 is already part of x^2 + 4x + 4
(x+4)/(x^2+4x+4)
14.) Factor both denominators..
4(y+2) and y(y+2)
So the common denominator would be 4y(y+2)
The first fraction is missing a "y" so multiply the numerator by y to get y^2
The second fraction is missing a "4" so multiply the numerator by 4 to get 4
(y^2 - 4)/(4y(y+2))
So can factor the numerator to get (y+2)(y-2). There if a (y+2) on top and bottom so they cancel out.
Answer: (y-2)/4y
9514 1404 393
Answer:
1.2 t/m³
Step-by-step explanation:
1 tonne is 1 Mg = 10⁶ g
1 m³ is (100 cm)³ = 10⁶ cm³
The conversion is ...
(1.2 g/cm³) · (1 t)/(10⁶ g) · (10⁶ cm³)/(1 m³)
= 1.2(10⁶)/(10⁶) t/m³
= 1.2 t/m³
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For this conversion, the numerical value does not change. Megagrams per cubic meter is the same ratio as grams per cubic centimeter.
Y = 4/x +3
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We are a bit mystified regarding the role of "15." in this question. We suspect it is an irrelevant question number.
7 pages , i would think that would be the answer :)
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