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3 years ago

Which source would be the most reliable to validate a claim?

Chemistry

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

In general, print publications with authors and listed sources tend to be reliable because they provide sources which readers can verify. Likewise, Web postings with a .gov (posted by the United States government) are both current and reliable.

Explanation:

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Problem PageQuestion The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium

Shalnov [3]

Answer:

1. 2NaN₃(s) → 2Na(s) + 3N₂(g)

2. 14.5 g NaN₃

Explanation:

The answer is incomplete, as it is missing the required values to solve the problem. An internet search shows me these values for this question. Keep in mind that if your values are different your result will be different as well, but the solving methodology won't change.

" The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces large volumes of nitrogen gas. 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen. 2. Suppose 71.0 L of dinitrogen gas are produced by this reaction, at a temperature of 16.0 °C and pressure of exactly 1 atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits. "

1. The reaction that takes place is:

2NaN₃(s) → 2Na(s) + 3N₂(g)

2. We use PV=nRT to calculate the moles of N₂ that were produced.

P = 1 atm

V = 71.0 L

n = ?

T = 16.0 °C ⇒ 16.0 + 273.16 = 289.16 K

1 atm * 71.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 289.16 K

n = 0.334 mol

Now we convert N₂ moles to NaN₃ moles:

0.334 mol N₂ * $\frac{2molNaN_{3}}{3molN_2}$ = 0.223 mol NaN₃

Finally we convert NaN₃ moles to grams, using its molar mass:

0.223 mol NaN₃ * 65 g/mol = 14.5 g NaN₃

6 0

3 years ago

If evaporation occurs what will change 0.70 molar solution of CuSO4

faust18 [17]

Answer:

A. Molarity will increase .

Explanation:

Molarity = moles of solute per litre of solution

= moles of solute / volume of solution

If evaporation occurs , volume of solution decreases and moles of solute remains constant . Hence denominator decreases and numerator remains constant .

Hence the molarity increases .

3 0

3 years ago

If light is what is virtually the fastest thing ever then how can the dark keep up with it?

Sav [38]

Dark is just absence of light like if the re container a and container b u nee to pour hcl from a to so a has hcl while b has absence of hcl

tell me if u need more examples.hope it helps

5 0

3 years ago

On a balance, you have beakers of AgNO3AgNO3 solution and NaClNaCl solution. When mixed, they will form AgCl(s)AgCl(s). What wil

statuscvo [17]

Explanation:

According to the law of conservation of mass, mass can neither be created nor it can be destroyed. But it can be simply transformed from one form to another.

Therefore, when $AgNO_{3}$ is added to NaCl then the compound formed will have same mass as that of reactants.

$AgNO_{3} + NaCl \rightarrow AgCl + NaNO_{3}$

Total mass of reactants is (169.87 + 58.44) g/mol = 228.31 g/mol

Total mass of products is (143.32 + 84.99) g/mol = 228.31 g/mol

Thus, we can conclude that mass of the new mixture will stay the same.

6 0

3 years ago

Part iii. Is the dissolution reaction of ammonium nitrate enthalpy favored?

lesya [120]

Answer:

No, it is not enthalpy favored since the chemical system gains energy.

Explanation:

The dissolution of ammonium nitrate in water is an endothermic process.

Endothermic process requires the system to gain energy to can dissolve the particles in water.

So, the reaction is not enthalpy favored.

3 0

3 years ago