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denpristay [2]
3 years ago
9

Which source would be the most reliable to validate a claim?

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Answer:

In general, print publications with authors and listed sources tend to be reliable because they provide sources which readers can verify. Likewise, Web postings with a .gov (posted by the United States government) are both current and reliable.

Explanation:

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statement 1,mass is conserved durning the reaction. statement 2 sum of mass and energy is conserved durning the reaction. which
maksim [4K]

Answer:

Explanation:

None of the statement is true for both chemical and nuclear reactions. In chemical reactions, mass is always conserved and the type of atoms are also conserved.

6 0
3 years ago
What are devices that move atomic nuclei at extremely high speeds
zloy xaker [14]
Particle accelerators is your answer 
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3 years ago
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* The cost of table salt and table sugar is Rs 15 per kg.
Vilka [71]

Cost per mole

Table salt : Rs 0.878

Table sugar : Rs 23.63

<h3>Further explanation</h3>

Given

Cost table salt (NaCl) = 15/kg

Cost table sugar(sucrose-C12H22O11) = 69/kg

Required

cost per mole

Solution

mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

\tt mol=\dfrac{1000~g}{58.5}=17.09~mol=Rs~15\rightarrow 1~mol=Rs~0.878

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

\tt mol=\dfrac{1000}{342}=2.92~mol=Rs~69\rightarrow 1~mol=Rs~23.63

6 0
3 years ago
An unknown gas effuses at one half the speed of oxygen. What is the molar mass of the unknown? It is either HBr or HI. Which gas
sertanlavr [38]

Answer:

HI.

Explanation:

  • Thomas Graham found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

Rate of effusion ∝ 1/√molar mass.

  • <em>(Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).</em>
  • An unknown gas effuses at one half the speed of that of oxygen.

∵ Rate of effusion of unknown gas = 1/2 (Rate of effusion of O₂)

∴ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = 2.

Molar mass of O₂ = 32.0 g/mol.

∵ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

∴  2.0 = (√molar mass of unknown gas) / √32.0.

( √molar mass of unknown gas) = 2.0 x √32.0

By squaring the both sides:

∴ molar mass of unknown gas = (2.0 x √32.0)² = 128 g/mol.

∴ The molar mass of sulfur dioxide = 80.91 g/mol and the molar mass of HI = 127.911 g/mol.

<em>So, the unknown gas is HI.</em>

<em></em>

5 0
3 years ago
The ________ produce egg cells and they _________ produce sperm.
Sergeu [11.5K]

Answer:

the females make eggs and males make the sperm

Explanation:

4 0
3 years ago
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