Answer: It is very important to know the activity tendencies of the elements. The activity tendencies tells us about whether the element is reactive or not.
In the redox-reaction where there is a need to know the oxidizing agent and reducing agent, we can know it easily from the activity tendencies. The elements lying above the reactivity series are better reducing agents.
In the substitution reactions, the activity tendencies helps us to know which element will replace the other. The element lying above in the series will replace the element lying below it.
where, N is an element that lies above in the reactivity series
M is an element that lies below in the reactivity series
Answer:
See balanced equations below
Explanation:
1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)
This is a single replacement reaction, involving an acid with a metal
2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂
3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)
4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)
B.
1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)
2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction
3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)
4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)
5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl
6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)
Sulfuric acid is capable of hurting the skin, eyes, paper, metals, and even stone in some cases.
Problem 57EDraw the Lewis structure for CO with an arrow representing the dipole moment. UseFigure 9.10 to estimate the percent ionic character of the CO bond. Step by step solutionStep 1 of 2Lewis structure of CO:Carbon has four valence electrons and oxygen has six valence electrons. If only one bond wereto be formed between carbon and oxygen atoms, carbon would have five electrons and oxygenwould have seven electrons.The single bond between these two atoms is not sufficient to lead to an octet on each atom . Tocomplete the octet of each atom in CO, we must employ a triple bond .A triple bond is formed bythe six electrons sharing between these two atoms and it is shown as follows.\nThe Lewis structure of CO with an arrow representing the dipole moment.The arrow towards anoxygen atom it represents is a highly electronegative atom.
