Protons and Neutrons is what determines the atomic mass. I cannot further explain this answer, however, I hope I helped!
Answer:
At anode - 
At cathode - 
Explanation:
Electrolysis of NaBr:
Water will exist as:
The salt, NaBr will dissociate as:
At the anode, oxidation takes place, as shown below.
At the cathode, reduction takes place, as shown below.
Answer:
C3H7NO2
Explanation:
The chemical formula of Alanine is C3H7NO2 and it belongs to almost all food category because it is present in one food of each food category such as dairy products, meat, nuts, soy, and whole grains etc. Alanine is a nonessential amino acid means that it does not directly obtained from the diet but it can be produced by the body using raw materials present in the food.
Answer:
a. Propanol
b. Propanone
c. Butanal
Explanation:
From the given information:
We are to state which of the given samples are more soluble in water.
The solubility of an organic molecule in water depends on the polarity of the given organic molecule. This solubility behaviour conforms with the general rule -"like dissolve like". Solubility is a means of comparing the extent to which different solutes can dissolve in a particular solvent at a definite temperature. Water is a polar solvent; therefore, an organic molecule that will also dissolve in water must be polar.
From the first pair, we have propane and propanol.
Propanol is more soluble in water than propane due to its polarity in water.
From the second pair:
Propanone is an alkanone (ketone group) with three carbon chain directly bonded to an oxygen double bond. At the same time, 3-hexanone has six carbon chain ketone group with the oxygen double bond located at the third carbon chain ( a hydrophobic "water-fearing" compound). Thus, the shorter the carbon chain, the more polar the organic molecule is and the more it is likely going to dissolve in water. Therefore, Propanone is more soluble in water than 3-hexanone.
From the third pair: The shorter the carbon chain, the more soluble in water it will become.
Butanal is the fourth element on the alkanal family group while hexanal is the sixth compound in the alkanal family group. As such, butanal is more soluble in water than hexanal.
Answer: The final concentration of 
at equilibrium is 0.36 M
Explanation:
Moles of 
= 0.64 mole
Volume of solution = 1.0 L
Initial concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.64 M 0M 0M
At eqm. conc. (0.64-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%5Ctimes%20%5BPCl_3%5D%7D%7B%5BPCl_5%5D%7D)
Now put all the given values in this expression, we get
By solving the term 'x', we get :
x = 0.36
Thus, the final concentration of at equilibrium is x = 0.36 M
