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Nat2105 [25]
3 years ago
7

What is the ratio of 3 and 8

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0
Hello there, 
The ratio from 3 to 8 is 3:8.

Hope you have a nice day! :)
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How many times can 56 go into 984
dybincka [34]

17 times evenly, all you have to do is divide 984 by 56 to get your answer.

5 0
3 years ago
Read 2 more answers
Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

5 0
3 years ago
A library charges a late return fee of 3.50 plus $0.15 per day that a book is returned late write a equation to find the total l
joja [24]
The equation would be:

3.50 + 0.15x

x represents each 'late day'
7 0
3 years ago
As a recruiter, you are asked to recruit 65 new sales associates for an organization. Traditionally, for the organization, 25% o
Lorico [155]

Answer: 1733.33 ≈ 1734 applicants

Step-by-step explanation:

Let x be the number of job applicants being looked at.

If 25% of applicants become job candidates, then number of job candidates = 0.25x

If 20% of job candidates receive job offers, then the number of job offers = 0.20 × 0.25x = 0.05x

If 75% of job offers are accepted, then number of accepted recruits = 0.75 × 0.05x = 0.0375x

This 0.0375x shows the number of new recruits which is equivalent to the 65 that is needed by the client if the recruiter.

By equating this 0.0375x to 65,we have:

0.0375x = 65

x = 65/0.0375

x= 1733.33 applicants, for whole number sake because we're dealing with humans, we approximate to 1734

5 0
3 years ago
Gene invested $400 at 4% interest compounded quarterly.<br> How much is in the account after 1 year?
Ivenika [448]

Answer:

$416.24

Step-by-step explanation:

4 0
3 years ago
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