All categories

2 years ago

Joshua sold a batch of tickets for carnival rides. The ratio of adult tickets to child tickets was 2:5.

Mathematics

1 answer:

schepotkina [342]2 years ago

3 0

The total number of adult tickets sold is 250.

<h3>What is the total number of adults tickets sold?
</h3>

Let the initial number of adult's ticket sold be represented with x
Let the initial number of children's ticket sold be represented with y

x / y = 2/5

Cross multiply :5x = 2y

y = 5/2

y = 2.5x

(x + 70) / (y + 300) = 1/3

Cross multiply :210 + 3x = 300 + y

Substitute for y

210 + 3x = 300 + 2.5x

300 - 210 = 3x - 2.5x

90 = 0.5x

x = 90 / 0.5

x = 180

Total tickets sold = 180 + 70 = 250

To learn more about ratios, please check: brainly.com/question/9194979

#SPJ1

You might be interested in

A conjunction is a statement formed by combining two statements with the word?

umka21 [38]

<span>A conjunction is a statement formed by combining two statements with the word "and".</span>

4 0

3 years ago

Is math<br><br> a. bad<br> b. bad<br> c. bad<br> d. all of the above

Elina [12.6K]

Answer:

Step-by-step explanation:

brainliest pls

7 0

3 years ago

Read 2 more answers

What is 5 = p over 4

Gnoma [55]

Since it's p over four, which is a fraction, multiply each side by four. p = 20

3 0

4 years ago

How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.

Vaselesa [24]

Answer:

see below

Step-by-step explanation:

$-2(4 - \frac{x}{2} )^{5} + C$

Think of the above as:

$-\frac{2}{1}$ * $(\frac{8}{2} - \frac{x}{2} )^{5} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{2^{5}} + C$

= $-\frac{2}{1}$ * $\frac{(8 - x)^{5}}{32} + C$

= $-\frac{1}{1}$ * $\frac{(8 - x)^{5}}{16} + C$

= $\frac{-1(8 - x)^{5}}{16} + C$

= $\frac{(-8 + x)^{5}}{16} + C$

Can flip it around to be...

$\frac{(x - 8)^{5}}{16} + C$

4 0

3 years ago

Subtract 3/y-2 - 1/y+3

Helen [10]

To subtract fractions, we need a common denominator.

$\frac{3}{y-2}$ - $\frac{1}{y+3}$

the common denominator will be (y-2)(y+3)

$\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}$
$\frac{3y + 9 - y + 2}{(y-2)(y+3)}$
$\frac{2y + 11}{(y-2)(y+3)}$

The answer above will be the simplified form.

3 0

4 years ago