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Vilka [71]
2 years ago
7

NEED HELP ASAP PLEASE

Mathematics
2 answers:
professor190 [17]2 years ago
7 0
No idea sorry! If I knew I would tell you
Mademuasel [1]2 years ago
6 0

Answer:

y = 2x^2 + 8x + 3

Step-by-step explanation:

Step 1: use the vertex form of the quadratic equation

y = a*(x - h)^2 + k

vertex = (-2, -5) = (h, k)

y = a*(x + 2)^2 - 5

Step 2: determine a using the given point

point = (0, 3)

y = a*(x + 2)^2 - 5

3 = a*(0+2)^2 - 5

3 + 5 = a*(2)^2

8 = a*4

a = 2

vertex equation is now y = 2*(x + 2)^2 - 5

Step 3: simplify vertex equation to standard quadratic equation

quadratic equation = Ax^2 + Bx + C

y = 2*(x + 2)^2 - 5

y = 2*(x^2 + 4x + 4) - 5

y = 2x^2 + 8x + 8 - 5

y = 2x^2 + 8x + 3

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Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

(x,y)\rightarrow (-y,x)

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(B)

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Therefore, the vertex of imare are  J''(4,1),  K''(2,-4) and  L''(3,-1). The graph is shown in figure (2).

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