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Vilka [71]
1 year ago
7

NEED HELP ASAP PLEASE

Mathematics
2 answers:
professor190 [17]1 year ago
7 0
No idea sorry! If I knew I would tell you
Mademuasel [1]1 year ago
6 0

Answer:

y = 2x^2 + 8x + 3

Step-by-step explanation:

Step 1: use the vertex form of the quadratic equation

y = a*(x - h)^2 + k

vertex = (-2, -5) = (h, k)

y = a*(x + 2)^2 - 5

Step 2: determine a using the given point

point = (0, 3)

y = a*(x + 2)^2 - 5

3 = a*(0+2)^2 - 5

3 + 5 = a*(2)^2

8 = a*4

a = 2

vertex equation is now y = 2*(x + 2)^2 - 5

Step 3: simplify vertex equation to standard quadratic equation

quadratic equation = Ax^2 + Bx + C

y = 2*(x + 2)^2 - 5

y = 2*(x^2 + 4x + 4) - 5

y = 2x^2 + 8x + 8 - 5

y = 2x^2 + 8x + 3

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Answer:

Answer

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(a) Coefficient of x

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(b) Degree of polynomial = highest degree of monomial with non-zero coefficient =7

(c) Constant term = Coefficient of x

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<h2>plz mark me as brainliest</h2>

5 0
3 years ago
Urgent!!!!!!!plzz
Nitella [24]

Answer:

too much reading, can you put more points.

(edit: OML SO SORRY -THOUGHT THIS WAS QUESTIONS)

Step-by-step explanation:

7 0
3 years ago
Four students were asked to write an expression which has terms that have a greatest common factor of 8c. The expressions provid
wel

Answer:

Wyatt wrote the correct expression

Step-by-step explanation:

Here we are to evaluate which of the students wrote an expression with the highest common factor being 8c

For Tanya; 32c + 16c; 16c( 2 + 1); This is wrong as the highest common factor is 16c

For Wyatt, we have 8c - 48cd; factorizing, we have 8c(1-6cd); This is correct

For Xavier we have 36c-24c; 8 is not a factor of 36, so it won’t work

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3 0
3 years ago
Read 2 more answers
What is the mixed number: 1 and 3/4 as a percent​
LenaWriter [7]

Answer:

175%

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8 0
2 years ago
What are the solutions to the equation (2x – 5)(3x – 1) = 0?
user100 [1]

Answer: x=\frac{5}{2}, x=\frac{1}{3}

Explanation:

The equation is:

(2x-5)(3x-1)=0

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.

This means that we can solve separately for the two terms:

2x-5=0\\3x-1=0

Solving the first equation:

2x-5=0\\2x=5\\x=\frac{5}{2}

Solving the second equation:

3x-1=0\\3x=1\\x=\frac{1}{3}

8 0
2 years ago
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