The compound which on combustion produces Carbon-di-oxide and water is carbohydrates.
- Percentage of Carbon = 6.98 / 17.41 x 100 = 40 %
- Percentage of Hydrogen = 15.08 / 17.41 x 100 = 86.61 %
- Percentage of Oxygen = 4.6 / 17.41 x 100 = 26.42 %
<h3>What is combustion reaction ?</h3>
Those reaction in which the Crabon present in the reatctant gets reacted with oxygen and produces Carbon-di-oxide.
It is an Exothermic Reaction.
<h3>Combustion of carbohydrate ;
![C_6H_1_2 O_6 + O_2 - > 6CO_2 +2H_2O](https://tex.z-dn.net/?f=C_6H_1_2%20O_6%20%2B%20O_2%20%20%20%20-%20%3E%206CO_2%20%2B2H_2O)
</h3>
To find out the percentage of C, H and O, we must know about there weight in the product.
Given,
Total weight of compund [Reactant] = 17.41 grams
Weight of carbon dioxide [Product] = 25.61 grams
Weight of water [Product]= 10.48 grams
Now, we need to find out the weight of C,H and O in the products ;
- Mass of Carbon = No. of Moles x Atomic weight
No. of Moles of Crabon =
x No. of C-atoms in molecule
No. of Moles of Crabon =25.61 / 44 = 0.58 x 1 = 0.58 moles
Mass of Carbon = 0.58 moles x 12 = 6.98 gm
- Mass of Hydrogen = No. of Moles x Atomic weight
No. of Moles of Hydrogen =
x No. of H-atoms in molecule
No. of Moles of Hydrogen =10.48/ 18 = 0.58 x 2 = 1.16 moles
Mass of Hydrogen = 1.16 moles x 12 = 15.08 gm
- Mass of Oxygen = Total weight of compound - (Weight of C & H)
= 17.41 grams - ( 15.08 gm + 6.98 gm)
Mass of Oxygen = 4.6 gm
Now,
Percentage of atom =
x 100
- Percentage of Carbon = 6.98 / 17.41 x 100 = 40 %
- Percentage of Hydrogen = 15.08 / 17.41 x 100 = 86.61 %
- Percentage of Oxygen = 4.6 / 17.41 x 100 = 26.42 %
Learn more about Percentage composition here ;
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