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Gala2k [10]
2 years ago
14

the combustion of 17.41 grams of a compound known to only contain carbon, hydrogen, and oxygen produced 25.61 grams of carbon di

oxide and 10.48 grams of water. a.) how much percentage of the compound is carbon? b.) how much percentage of the compound is hydrogen? c.) how much percentage of the compound is oxygen?
Chemistry
1 answer:
Svet_ta [14]2 years ago
3 0

The compound which on combustion produces Carbon-di-oxide and water is carbohydrates.

  • Percentage of Carbon = 6.98 / 17.41 x 100 = 40 %
  • Percentage of Hydrogen = 15.08 / 17.41 x 100 = 86.61 %
  • Percentage of Oxygen = 4.6 / 17.41 x 100 = 26.42 %

<h3>What is combustion reaction ?</h3>

Those reaction in which the Crabon present in the reatctant gets reacted with oxygen and produces Carbon-di-oxide.


It is an Exothermic Reaction.

<h3>Combustion of carbohydrate ;

C_6H_1_2 O_6 + O_2    - > 6CO_2 +2H_2O</h3>

To find out the percentage of C, H and O, we must know about there weight in the product.

Given,

Total weight of compund [Reactant] = 17.41 grams

Weight of carbon dioxide [Product] = 25.61 grams

Weight of water [Product]= 10.48 grams

Now, we need to find out the weight of C,H and O in the products ;

  • Mass of Carbon = No. of Moles x Atomic weight


No. of Moles of Crabon =   \frac{Given \\ weight\\  of\\  the\\  compound}{Molecular\\ weight\\  of\\  the compound} x No. of C-atoms in molecule                          

No. of Moles of Crabon =25.61 / 44 = 0.58 x 1 = 0.58 moles

Mass of Carbon = 0.58 moles x 12 = 6.98 gm

  • Mass of Hydrogen = No. of Moles x Atomic weight

No. of Moles of Hydrogen =   \frac{Given \\ weight\\  of\\  the\\  compound}{Molecular\\ weight\\  of\\  the compound} x No. of H-atoms in molecule                          

No. of Moles of Hydrogen =10.48/ 18 = 0.58 x 2 = 1.16 moles

Mass of Hydrogen = 1.16 moles x 12 = 15.08 gm

  • Mass of Oxygen = Total weight of compound - (Weight of C & H)

                                       =   17.41 grams - ( 15.08 gm + 6.98 gm)
Mass of Oxygen  = 4.6 gm

Now,

Percentage of atom =  \frac{Mass \\ of \\ Atom}{Total\\  weight \\ of\\  compound}   x 100

  • Percentage of Carbon = 6.98 / 17.41 x 100 = 40 %
  • Percentage of Hydrogen = 15.08 / 17.41 x 100 = 86.61 %
  • Percentage of Oxygen = 4.6 / 17.41 x 100 = 26.42 %

Learn more about Percentage composition here ;

brainly.com/question/20065048

#SPJ1

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Svetllana [295]

Answer:

Number of moles = 10.6 mol

Explanation:

Given data:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

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Formula:

Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

C₆H₈O₇ = 72.06 + 8.064+112

C₆H₈O₇ = 192.124g/mol

Number of moles = 2030 g/ 192.124g/mol

Number of moles = 10.6 mol

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