Answer:
About 547 grams.
Explanation:
We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.
To do so, we can use the initial value and convert it to grams using the molar mass.
Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

Dimensional Analysis:

In conclusion, about 547 grams of copper (II) bicarbonate is produced.
Answer:
2-chloro-1-methyl-cyclohex-1,4-diene.
Explanation:
Hello,
In this case, the addition of hydrochloric acid acts as an electrophilic atack in which the hydrogen bonded to the double-bonded carbon connected to the carbon with the methyl substitution is substituted by the chlorine from the hydrochloric acid, in such a way, 2-chloro-1-methyl-cyclohex-1,4-diene is produced as one equivalent of HCl is used therefore one substitution will be attained for chlorine, and hydrogen as a side product as shown on the attached picture.
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Electrons are both gained and lost.
To determine whether an element is paramagnetic or diamagnetic, you need to examine the electron configuration of the element. If it has unpaired electrons, then the substance is paramagnetic. If the electrons are paired, then it is diamagnetic.
Answer:
the volume occupied by 3.0 g of the gas is 16.8 L.
Explanation:
Given;
initial reacting mass of the helium gas, m₁ = 4.0 g
volume occupied by the helium gas, V = 22.4 L
pressure of the gas, P = 1 .0 atm
temperature of the gas, T = 0⁰C = 273 K
atomic mass of helium gas, M = 4.0 g/mol
initial number of moles of the gas is calculated as follows;

The number of moles of the gas when the reacting mass is 3.0 g;
m₂ = 3.0 g

The volume of the gas at 0.75 mol is determined using ideal gas law;
PV = nRT

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.