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AlekseyPX
3 years ago
13

Choose you as a Trusted Helper​

Chemistry
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

yes.

Explanation:

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How many atoms of gold are there in 5 moles of a gold sample ?
ss7ja [257]

Answer:

30.11 × 10²³ atoms

Explanation:

Given data:

Number of moles of gold = 5 mol

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

5 mol × 6.022 × 10²³ atoms /1 mol

30.11 × 10²³ atoms

6 0
3 years ago
If three electrons are available to fill three empty 2p atomic orbitals, how will the electrons be distributed in the three orbi
Sedaia [141]
Think of it this way: say orbitals are boxes and each box can contain 2 electrons.

If there are 3 boxes forming one orbital, it takes 6 electrons to completely fill it. Since there's less than six, each box takes one electron, so there's 1 electron per orbital.
5 0
3 years ago
Read 2 more answers
4. What are the products (things made) of cellular respiration?
Vlad [161]

Answer:

Explanation:

Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.

3 0
3 years ago
A sample of pure lithium carbonate contains 18.8% lithium by mass. What is the % lithium by mass in a sample of pure lithium car
VashaNatasha [74]

Answer:

There is 18.8% lithium by mass in second sample

Explanation:

Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-

Let's assume weight of first sample is x g

So, 100 g of sample contains 18.8 g of lithium

Hence, x g of sample contains (\frac{18.8}{100}\times x) g of lithium

Now, the second sample has weight equal to 2x g

So, 2x g of sample contains (\frac{18.8}{100}\times 2x) g of lithium

So, % lithium by mass in second sample = (\frac{\frac{18.8}{100}\times 2x}{2x})\times 100 % = 18.8%

4 0
4 years ago
What is the volume of a balloon that contains 3.7 moles of helium at 75°C<br> and 5.1 atm?
postnew [5]

Answer: your question is easy 21 L

8 0
3 years ago
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