Question

I need help with this simplify 5/4+4(3/4−1/2)^2

Answer 1

Answer:

2 1/4

Step-by-step explanation:

first do 4*3/4-4*1/2 because of order order of operations.

12/4-4/2=3-2=1

then do 1^2 because you do exponents before addition.

1^2=1*1=1

5/4+1=5/4+4/4=9/4

9/4=2 1/4

Answer 2

$\frac{5}{4}+4\left(\frac{3}{4}-\frac{1}{2}\right)^2 =$

$\frac{3}{4}-\frac{1}{2} =\frac{3}{4}-\frac{2}{4}=$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}-\frac{b}{c}=\frac{a-b}{c}$

$=\frac{3-2}{4}$

$\mathrm{Subtract\:the\:numbers:}\:3-2=1$

$=\frac{1}{4}$

$=\frac{5}{4}+4\cdot \frac{1}{4}^2$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}^n=\frac{a^n}{c^n}$

$=\frac{5}{4}+4\cdot \frac{1}{16}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \:a+\frac{b}{c}=\frac{ac+b}{c}$

$=\frac{4\cdot \frac{1}{16}\cdot \:4+5}{4}$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:4=16$

$\frac{16\cdot \frac{1}{16}+5}{4} =\frac{6}{4} =\boxed{\frac{3}{2}}$

$\mathrm{I\:hope\:that\:I\:helped\:you\:!}$