Answer:
2
Step-by-step explanation:
12-2= m(2+3)
m= 10/5=2
Answer:
Step-by-step explanation:
<u>Volume Of A Regular Solid</u>
When a solid has a constant cross-section, the volume can be found by multiplying the area of the base by the height. The area of a trapezium is
where 
and 
are the lengths of the parallel sides and h the distance between them.
The figure shows a solid with a trapezoid as the constant cross-section and a height x. The volume of the solid is
The image doesn't explicitly say if the length of 4.5 is the height of the trapezium or the length of that side. We'll assume the first, so our data is:
We now compute the volume
Answer:
π 
Step-by-step explanation: diameter=10 in
radius=
=
=5 in
volume=
=
x π =π
50 is a composite number. 50 = 1 x 50; 2 x 25; or 5 x 10. Factors of 50: 1, 2, 5, 10, 25, 50.
Prime factorization: 50 = 2 x 5 x 5.
Answer:
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Step-by-step explanation:
The equation for the volume of a pyramid of base area B and height h is
V = (1/3)·B·h. Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown. First we find the height of this pyramid, and then the slant height.
V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.
Now to find the slant height of this pyramid: That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).
Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
