Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer:
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8 ( 4 - x ) = 7x + 2
32 - 8x = 7x + 2
-7x -7x
--------------------------
32 - 15x = 2
-32 -32
----------------------------
-15x = -30
/-15 /-15
x = 2.
Answer:

Step-by-step explanation:

Isolate x on one side of the equation.
Find the value of x.
First, multiply -1 from both sides.
(-3/4x)(-1)<12(-1)
Solve.
12(-1)=-12
3/4x<-12
Next, multiply 4 from both sides.
4*3/4x<4(-12)
Solve.
Multiply the numbers from left to right.
4(-12)=-48
3x<-48
Then, divide by 3 from both sides.
3x/3<-48/3
Solve.
Divide the numbers from left to right.
-48/3=-16
X<-16

The correct answer is x<-16.