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2 years ago

Talia attended a 555-day math camp that lasted \dfrac56

Mathematics

1 answer:

Vaselesa [24]2 years ago

6 0

Complete Question

Talia attended a 5 -day math camp that lasted 5/6 of an hour each day. How many hours did Talia spend at the math camp?

Answer:

4 1/6 hours

Step-by-step explanation:

1 day = 5/6 hour

5 days = x

Cross Multiply

x = 5/6 × 5 days

x = 25/6 hours

x = 4 1/6 hours

Therefore, Talia spent 4 1/6 hours at camp.

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Ozzie has a coupon for 5% off any purchase in his favorite bakery. When Ozzie stops to buy some cookies, he discovers that all c

maria [59]

Answer:

Step-by-step explanation:

you need to first do 5.89- [(5.89 * 15)/100]=5.89-0.8835=5.0065

then 5.0065 * 2 = 10.013 because it is 15% each dozen then

[(10.013 * 5)/100] =0.50065 then 10.013 - 0.50065 = 9.51235

and lastly (9.51235 * 7)/100 = 0.6658645

finally 9.51235 + 0.6658645= 10.1782145

and then you just need to round it to the nearest hundredths and you will get 10.18

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2 years ago

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If < 1 = 125, what is < 7?

nordsb [41]

Answer:

875

Step-by-step explanation:

125 x 7 = 875

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2 years ago

I need helphrdugdgdggdhd

oee [108]

Answer: the first box

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Step-by-step explanation:

25.09 is more than 25.018 because 0.09 is greater than 0.01

25.09-25.018=0.072

7 0

3 years ago

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11^9–11^8+11^7 is divisible by 3 and 37.

vodomira [7]

11^9 -11^8 + 11^7 = 2163075981

2163075981/3 = 721025327

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Yes it is divisible by both 3 and 37

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3 years ago

Double angle identity. Just 5 questions. Really need help as my teacher has been frustrated with me

BartSMP [9]

The double angle identities are

$\sin(2x)=2\sin x\cos x$

$\cos(2x)=\cos^2x-\sin^2x$

Then

$2\sin\dfrac\pi6\cos\dfrac\pi6=\sin\left(\dfrac{2\pi}6\right)=\sin\dfrac\pi3$

$\cos^2\dfrac\pi{10}-\sin^2\dfrac\pi{10}=\cos\left(\dfrac{2\pi}{10}\right)=\cos\dfrac\pi5$

The second identity together with the Pythagorean identity, $\sin^2x+\cos^2x=1$ , gives us another equivalent expression:

$\cos^2x-\sin^2x=\cos^2x-(1-\cos^2x)=2\cos^2x-1$

$2\cos^2(0.5)-1=\cos(2\cdot0.5)=\cos1$

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3 years ago

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