Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
3 less than twice a number x.
Twice a number would be the x multiplied by 2, and 3 less would be 3 subtracted by 2*x.
2x-3 <- The numeral form.
I hope this helps!
~kaikers
The answer is 2 ODD vertices :)
The correct number value would be 280
It's a deal.
Tell us the ratio, and we'll get right to work on it.