If it’s a slope- intercept form/ y=mx+b then it’s y=1x+0 because each time it goes up one and over one which is 1/1 or 1 whole and the y-intercept is at (3,0) and we use the Y which is 0
Answer:
a = 6 and b = -1.
Step-by-step explanation:
To find the maximum value of y = -x²+ ax + b we differentiate it with respect to x to find the value of x at which it is maximum.
So dy/dx = d(-x²+ ax + b)/dx = -2x + a
we equate it to zero.
-2x + a = 0
-2x = -a
a = 2x
Now, given that x = 3 at the maximum value,
a = 2x = 2(3) = 6
Also, substituting y = 8 and x = 3 into y, we have
y = -x²+ ax + b
8 = -(3)²+ a(3) + b
8 = -9 + 3a + b
3a + b = 8 + 9
3a + b = 17
So, b = 17 - 3a
substituting a = 6, we have
b = 17 - 3(6)
b = 17 - 18
b = -1
So, a = 6 and b = -1.
Answer:
x ≈ 31.9
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos15° = 
= 
( multiply both sides by 33 )
33 × cos15° = x , then
x ≈ 31.9 ( to the nearest tenth )
