Answer:
Water gradually degrades them until the metal parts rust and the other materials deteriorate.
Explanation:
Strong and good for you bro
<h3>
Answer:</h3>
Empirical formula is CrO
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of sample of Chromium as 7.337 gram
- Mass of the metal oxide formed as 9.595 g
We are required to determine the empirical formula of the metal oxide.
<h3>Step 1 ; Determine the mass of oxygen used </h3>
Mass of oxygen = Mass of the metal oxide - mass of the metal
= 9.595 g - 7.337 g
= 2.258 g
<h3>Step 2: Determine the moles of chromium and oxygen</h3>
Moles of chromium metal
Molar mass of chromium = 51.996 g/mol
Moles of Chromium = 7.337 g ÷ 51.996 g/mol
= 0.141 moles
Moles of oxygen
Molar mass of oxygen = 16.0 g/mol
Moles of Oxygen = 2.258 g ÷ 16.0 g/mol
= 0.141 moles
<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>
Mole ratio of Chromium to Oxygen
Cr : O
0.141 mol : 0.141 mol
1 : 1
Empirical formula is the simplest whole number ratio of elements in a compound.
Thus the empirical formula of the metal oxide is CrO
Answer : The correct option is, (E) 6 moles.
Explanation : Given,
Moles of nitrogen = 2 moles
The given balanced chemical reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of nitrogen gas react with 3 moles of hydrogen gas
So, 2 mole of nitrogen gas react with 
moles of hydrogen gas
Therefore, the number of moles of hydrogen gas needed to react with 2 moles of nitrogen gas is, 6 moles.
