Answer:
11 meters
Step-by-step explanation:
Lets say that w = width of the rectangle, to start. If the length of the rectangle is 3 meters greater than 2 times the width, the length of the rectangle is equal to 3 + 2w.
The perimeter of the rectangle is 2 * length of rectangle + 2 * width of the rectangle. With the perimeter being equal to 30 and width being w and length being 2w+3:
The perimeter of the rectangle is 2(w) + 2(2w+3) = 30.
We first need to find out w first, which will give us the width of the rectangle. Taking it step by step, we get:
2w + 4w + 6 = 30
6w + 6= 30
6w = 24 which is done by subtracting both sides by 6 to put the variables on one side and the values on the other side
w = 4 which is done by dividing 6 on both sides
Ultimately, this gets width to be 4 meters. Now that we found the width, we need to plug w = 4 into the equation we set up for length which is 2w+3.
That being said, the ANSWER is:
length of rectangle = 2(4)+3 = 11 meters
Hope this helps! :)
X = k x y
21 = k x 3
k = 7
x = 7y
x = 7(10)
x = 70
~Hello There!~
Product means they multiply to make 6
Think of numbers that multiply to make six:
1 x 6
6 x 1
3 x 2
2 x 3
The largest out of those is clearly 6 x 1 which makes 61
Hope This Helps You!
Good Luck :)
Have A Great Day ^_^
- Hannah ❤
Answer:
h(-1) is -1, h(-0.5) is 0 and h(1) is 1.
Step-by-step explanation:
functions :- an expression, rule or law that defines relationship between one variable and another variable. When a certain condition is fulfilled, then the result is corresponding to that condition.
In the function it is given that when x∈(-2,-1] then we get -1. Now here x=-1 satisfies the given condition. So, the answer will be -1.
In the function it is given that when x∈(-1,0] then we get 0. Now here x=-0.5 lies in the range (-1,0]. So, the answer is 0.
In the function it is given that when x∈(0,1] then we get 1. Clearly, x=1 satisfies this range of values. So, we get 1.
Hence, the Answer is h(-1) = -1, h(-0.5) = 0 and h(1) = 1.
know more about functions at brainly.com/question/15912209
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