The first one
You start at -2 and go up 1 and to the right 1
Answer: OPTION A.
Step-by-step explanation:
You can observe that in the figure CDEF the vertices are:

And in the figure C'D'E'F' the vertices are:

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:
For C'(-8,-4) and C(-2,-1):

Let's choose another vertex. For E'(8,8) and E(2,2):

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.
Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:
→
1.
a.) 2q + 5r
2(7) + 5(-2)
14 - 10 = 4
b.) 3(p + 6) + q + r Plug in the numbers
3(5 + 6) + 7 - 2 Solve inside the parentheses first
3(11) + 7 - 2
33 + 5 = 38
2.
a.) m(3m + 4n)
2(3(2) + 4(3))
2(6 + 12)
2(18) = 36
b.) n²(m + p²)
(3)²(2 + (-5)²)
9(2 + 25)
9(27) = 243
c.) 3m(8 + n) + n²
3(2) (8 + 3) + 3²
6(11) + 9
66 + 9 = 75
Graph the equation in a graphing calculator or in the table in a regular calculator and look for the zero on the x axis and the y axis
Answer:
0.9855 or 98.55%.
Step-by-step explanation:
The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.