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Dmitry [639]
2 years ago
13

Type the correct answer in the box. Rewrite the quadratic function in the form that best reveals the zeros of the function. f(x)

=2(2x2+4x)+3
Mathematics
1 answer:
sergey [27]2 years ago
5 0

Try this suggested option:

Step-by-step explanation:

f(x)=2(2x²+4x)+3; ⇔

f(x)=4(x²+2x)+3; ⇔

f(x)=4(x²+2x+1)+3-4; ⇔

f(x)=4(x+1)²-1; ⇔

f(x)=(2x+1)(2x+3).

Then the roots are:

\left[\begin{array}{ccc}x=-1.5\\x=-0.5\end{array}.

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Answer:

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Step-by-step explanation:

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pishuonlain [190]

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Step-by-step explanation:

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Enter the equation of the circle with the given center and radius. Center: (−2, −5); radius= 1
statuscvo [17]

Answer:

(x + 2)^2 + (y + 5)^2 = 1

Step-by-step explanation:

Equation of a circle:

The equation of a circle with center (x_0,y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

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This means that x_0 = -2, y_0 = -5, r = 1. So

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6 0
3 years ago
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Juliette [100K]
3(x+1) = -2(x-1) + 6
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Step-by-step explanation:

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