Answer:
Intercepts:
x = 0, y = 0
x = 1.77, y = 0
x = 2.51, y = 0
Critical points:
x = 1.25, y = 4
x = 2.17
, y = -4
x = 2.8, y = 4
Inflection points:
x = 0.81, y = 2.44
x = 1.81, y = -0.54
x = 2.52, y = 0.27
Step-by-step explanation:
We can find the intercept by setting f(x) = 0
where n = 0, 1, 2,3, 4, 5,...
Since we are restricting x between 0 and 3 we can stop at n = 2
So the function f(x) intercepts at y = 0 and x:
x = 0
x = 1.77
x = 2.51
The critical points occur at the first derivative = 0
or
where n = 0, 1, 2, 3
Since we are restricting x between 0 and 3 we can stop at n = 2
So our critical points are at
x = 1.25, 
x = 2.17
, 
x = 2.8, 
For the inflection point, we can take the 2nd derivative and set it to 0
We can solve this numerically to get the inflection points are at
x = 0.81, 
x = 1.81, 
x = 2.52, 
Answer:
No, because it has repeating domains (x-values) which is -2
Step-by-step explanation:
A function should not have repeating x-values.
Answer:
A and B are correct
Step-by-step explanation:
if x:y is 1:3 then x is 1 and y is 3
1/3 of 3 is 1 so A is correct
3/4(1+3) is 3 so B is correct
But
1/4 × 3 is not 1 so C is not correct
3/4 ×1 is not 3 so D isn't correct
<h2>
Answer with explanation:</h2>
In statistics, The Type II error occurs when the null hypothesis is false, but fails to be rejected.
Given : Suppose the null hypothesis, 
, is: Darrell has enough money in his bank account to purchase a new television.
Then , Type II error in this scenario will be when the null hypothesis is false, but fails to be rejected.
i.e. Darrell has not enough money in his bank account to purchase a new television but fails to be rejected.
