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iris [78.8K]
2 years ago
6

The slope of the line below is 2. Use the coordinates of the labeled point to find the point-slope equation of the line. 

Mathematics
1 answer:
IgorLugansk [536]2 years ago
6 0

Answer:

A. y + 6= -2(x - 4)

Step-by-step explanation:

Let A(a , b) be a point of the line

and m be the slope.

The equation of the line in Point-slope form :

y - b = m (x - a).

…………………………

Given :

Slope = -2

A(4 , -6)

Then

Point-slope equation : y + 6= -2(x - 4)

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Answer:

Common difference (d) = -5

Step-by-step explanation:

formula=>

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=> -15 = 3d

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3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
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