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Fofino [41]
1 year ago
12

A fighter tank targets an enemy helicopter flying at an altitude of 1250 ft. If the ground

Mathematics
1 answer:
madam [21]1 year ago
7 0

By using trigonometric relations, we will see that the angle of elevation must be 55°.

<h3>How to find the angle of elevation?</h3>

We can see this as a right triangle, where one cathetus measures 1250ft (altitude) and the other cathetus measures 875ft.

The angle of elevation is the angle such that the adjacent cathetus is the one measuring 875ft.

Then we can use the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

tan(a) = 1250ft/875ft

To find the angle of elevation, we can use the inverse tangent function:

a = Atan(1250ft/875ft) = 55°

The angle of elevation must be 55 degrees.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

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Solve 2x2 – 6x + 10 = 0 by completing the square.
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Answer:

Step-by-step explanation:

2x^2-6x+10=0

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2(x-(3/2))^2-9/4)+10=0

2(x-(3/2))^2+10-9/2=0

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2(x-(3/2))^2=-11/2

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check al
Alla [95]

Let's rewrite each equation in the Slope-Intercept Form of the Equation of a Line. First, let's start with the main equation:


\bullet \ 5x-2y=-6 \therefore y=\frac{5}{2}x+3


Then, our options are the following:

A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \therefore y=-\frac{2}{5}x-2 \\ \\ C) \ 2x-5y=-10 \therefore y=\frac{2}{5}x+2 \\ \\ D) \ y+4=-\frac{2}{5}(x-5) \therefore y=-\frac{2}{5}x-2 \\ \\ E) \ y-4=\frac{5}{2}(x + 5) \therefore y=\frac{5}{2}x+\frac{33}{2}


For two perpendicular lines it is true that the product of its slopes is:

m_{1}m_{2}=-1


m_{1}m_{2}=-1 \\ \\ m_{1} \ is \ the \ slope \ of \ y=\frac{5}{2}x+3, \ that \ is, \ m_{1}=\frac{5}{2} \\ \\ Then, \ the \ slope \ of \ a \ perpendicular \ line \ is: \\ \\ m_{2}=-\frac{2}{5}


According to this, only A) B) and D) might be the perpendicular lines we are looking for. Notice that these lines are the same. The other condition is that the line must pass through the point (5, -4). By substituting this point in the equation, we have:

y = -\frac{2}{5}x-2 \\ \\ -4=-\frac{2}{5}(5)-2 \\ \\ -4=-2-2 \\ \\ \boxed{-4=-4} \ True!


Finally, the right answer are:

A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \\ \\ D) \ y+4=-\frac{2}{5}(x-5)

8 0
2 years ago
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cluponka [151]

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● √(10/3) × -√(10/3) = -10/3

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