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ExtremeBDS [4]
3 years ago
5

The square root of -12 × the square root of -9 (THIS IS AN ALGEBRA 2 QUESTION)

Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

\sqrt{-12} = 2\sqrt{3} i\\\sqrt{-9}= 3i\\3i * 2\sqrt{3}i = -6\sqrt{3

Step-by-step explanation:

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Which is an asymptofe of the graph the function y=cot(x-2π/3)
Shalnov [3]

Hello.


C) x=4π/3


The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).


Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.


Have a nice day



5 0
3 years ago
Can anyone help me???
Alenkinab [10]

Answer: think A

Step-by-step explanation:

3 0
2 years ago
C
Volgvan

The arc angle AC is measured as 55 degrees.

<h3>How to find arc angle?</h3>

If two secant intersect in the exterior of a circle, then the measure of the angle formed is half the positive difference of the arcs intercepted.

Therefore, the secants intersect outside the circle at point E.

The arc angle AC can be found as follows:

Therefore,

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

arc angle AC = x

arc angle BD = 23 degrees.

m∠BED = 16 degrees.

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

16 = 1 / 2 (x - 23)

16 = 1 / 2x - 23 / 2

16 + 11.5 = 0.5x

27.5 = 0.5x

x = 27.5 / 0.5

x = 55 degrees.

Therefore,

arc angle AC = 55 degrees.

learn more on arc angle here: hhttps://brainly.com/question/23117081

#SPJ1

7 0
1 year ago
Please help me understand this.Will mark brainlyist to right answer no links!!!
SSSSS [86.1K]
Wowowow
Answer:45
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4 0
3 years ago
Point P' is the image of the point P after a counterclockwise rotation of 90 degress about the origin. If the coordinates of poi
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