An object is moving along the x axis. At t = 5.6 s, the object is at x = +3.0 m and has a velocity of +5.7 m/s. At t = 8.5 s, it

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is at x = +9.0 m and its velocity is -1.0 m/s. Find the average acceleration between t = 5.6 s and t = 8.5 s.

1 answer:

Debora [2.8K] · Answer 1 · 2023-03-07T09:51:40+03:00

The average acceleration between t = 5.6 s and t = 8.5 s is 2.31 m/s²

<h3>What is acceleration?</h3>

Acceleration is defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

An object is moving with initial velocity u =5.7 m/s and its final velocity v= -1.0 m/s.

Time taken for the change in speed, t= 8.5 - 5.6 = 2.9 seconds

The acceleration is given by

a = (-1 - 5.7)/ 2.9

a = - 2.31 m/s²

|a | = 2.31 m/s²

Thus, the object's acceleration is 2.31 m/s²

Learn more about acceleration.

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